Question: Recall that the substitution x = a sec implies either x a (in which case 0 < /2 and tan
Recall that the substitution x = a sec θ implies either x ≥ a (in which case 0 ≤ θ < π/2 and tan θ ≥ 0) or x ≤ -a (in which case π/2 < θ ≤ π and tan θ ≤ 0).
Graph the function
on its domain. Then find the area of the region R1 bounded by the curve and the x-axis on [-12, -12/√3] and the area of the region R2 bounded by the curve and the x-axis on [12/√3, 12]. Be sure your results are consistent with the graph.
1 f(x) xVx? 36
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8 15 10 12 1 T 123 xx 36 Let 26 sec 0 so that dx 6 sec 0 ... View full answer
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