Recall that the substitution x = a sec implies either x a (in which case 0 < /2 and tan

Recall that the substitution x = a sec θ implies either x ≥ a (in which case 0 ≤ θ < π/2 and tan θ ≥ 0) or x ≤ -a (in which case π/2 < θ ≤ π and tan θ ≤ 0).

Show that

secx + C = tan1 Vx 1 + C - secx + C = -tan Vx 1 + C if x > 1 if x < -1. dx xVx? .2