Recall that the substitution x = a sec implies either x a (in which case

Recall that the substitution x = a sec θ implies either x ≥ a (in which case 0 ≤ θ < π/2 and tan θ ≥ 0) or x ≤ -a (in which case π/2 < θ ≤ π and tan θ ≤ 0).

Show that

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secx + C = tan¬1 Vx² – 1 + C - secx + C = -tan Vx² – 1 + C if x > 1 if x < -1. dx xVx? .2 х