Assuming that the combustion of hydrogen gas provides three times as much energy per gram as gasoline,
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Assuming that the combustion of hydrogen gas provides three times as much energy per gram as gasoline, calculate the volume of liquid H2 (density = 0.0710 g/mL) required to furnish the energy contained in 80.0 L (about 20 gal) of gasoline (density = 0.740 g/mL). Calculate also the volume that this hydrogen would occupy as a gas at 1.00 atm and 25°C.
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The mass of 800 L of gasoline is 1000 mL 0740 g mL 1 L 800 L X Since H furnishes three t...View the full answer
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