Given the matrix [mathbf{C}(z)=left[begin{array}{cc}R_{0}(z) & R_{1}(z) z^{-1} R_{1}(z) & R_{0}(z)end{array} ight]] show that its inverse is pseudo-circulant.
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Given the matrix
\[\mathbf{C}(z)=\left[\begin{array}{cc}R_{0}(z) & R_{1}(z) \\z^{-1} R_{1}(z) & R_{0}(z)\end{array}\right]\]
show that its inverse is pseudo-circulant.
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