1 00 x 10 3 mol PCl 5 is introduced into a 250 0 mL flask, and equilibrium is established at 284 C PCl 5 (g) PCl 3 (g) Cl 2 (g) The quantity of Cl 2 (g) present at equilibrium is found to be 9 65 x 10 4 mol What is the value of K c for the dissociation reaction at 284 C ...

To calculate the value of Kc for the dissociation reaction of PCl5 at 284 C we need to use the equil ...

1.00 x 10 -3 mol PCl 5 is introduced into a 250.0 mL flask, and equilibrium is...

Question:

1.00 x 10^-3 mol PCl₅is introduced into a 250.0 mL flask, and equilibrium is established at 284 °C: PCl₅(g) ⇌ PCl₃(g) + Cl₂(g). The quantity of Cl₂(g) present at equilibrium is found to be 9.65 x 10^-4 mol. What is the value of K_c for the dissociation reaction at 284 °C ?