The state of an ideal gas with C P = (5/2)R is changed from P = 1
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The state of an ideal gas with CP = (5/2)R is changed from P = 1 bar and V1t = 12 m3 to P2 = 12 bar and V2t = 1 m3 by the following mechanically reversible processes:
(a) Isothermal compression.
(b) Adiabatic compression followed by cooling at constant pressure.
(c) Adiabatic compression followed by cooling at constant volume.
(d) Heating at constant volume followed by cooling at constant pressure.
(e) Cooling at constant pressure followed by heating at constant volume.
Calculate Q, W, ΔUt, and ΔHt for each of these processes, and sketch the paths of all processes on a single PV diagram.
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Related Book For
Introduction To Chemical Engineering Thermodynamics
ISBN: 9781259696527
8th Edition
Authors: J.M. Smith, Hendrick Van Ness, Michael Abbott, Mark Swihart
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