Question: 13. Lead ions can be precipitated from solution with KCl according to the reaction: Pb2+(aq)+2KCl(aq)PbCl2(s)+2K+(aq) When 28.5gKCl is added to a solution containing 25.7gPb2+, a

13. Lead ions can be precipitated from solution with KCl according to the reaction: Pb2+(aq)+2KCl(aq)PbCl2(s)+2K+(aq) When 28.5gKCl is added to a solution containing 25.7gPb2+, a PbCl2 precipitate forms. The precipitate is filtered, dried, and found to have a mass of 29.4g. Determine the limiting reactant, theoretical yield of PbCl2, and percent yield for the reaction

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