Question: 5. Consider the balanced equation below in which 10.86 grams of PCl5 reacts with 13.58 grams of AsF3.3(30.94)+s(3s.45)=270.16 3PCl5+5AsF33PF5+5AsCl3s(74.92)+3(18.90)=431.54 What is the excess reactant? A.

5. Consider the balanced equation below in which 10.86 grams of

5. Consider the balanced equation below in which 10.86 grams of PCl5 reacts with 13.58 grams of AsF3.3(30.94)+s(3s.45)=270.16 3PCl5+5AsF33PF5+5AsCl3s(74.92)+3(18.90)=431.54 What is the excess reactant? A. PCCl5 B. AsF3 How many grams of excess reactant are left over after the reaction is complete? grams

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