$9\mathrm{.}2$

Allowable Stress Design

To the nearest $\frac{1}{16}in,$ determine the required thickness of member $B$ and the diameter of the pins at A and $B$ if the allowable normal stress for member $BC$ is ${}_{\text{a}\text{l}\text{l}\text{o}\text{w}}=29$ksi, and the allowable shear stress for the pins is ${}_{\text{a}\text{l}\text{l}\text{o}\text{w}}=10$ksi.

Hint: This is a somewhat long problem. You'll first have to calculate the force of the members on pins A and B from "old" statics $($remember: the force of a member on the pin is equal and opposite to the force of a pin on the member$).$

Then you're going to have to walk through THREE failure modes:

$($a$)$ BC "ripping apart" somewhere in the middle due to tension,

$($b$)$ "Double$-$shear" at pin B$,$

$($c$)$ "Single$-$shear" at pin A$.$

There could be even more failure modes, but you'd need more info about the beams for that.