Question: A Hooke's Law object under compression has spring constant 5.00 106 N m-; initial load is -1.50 104 N. If deformation changes by Ax

A Hooke's Law object under compression has spring constant 5.00 106 N m-; initial load is -1.50 104 N. If deformation changes by Ax = +2.00 mm... What is the change in strain potential energy? A. -20.0 J B. -2.00 x 107 J C. 20.0 J D. 10.0 J E. 1.00 x 107 J W = AE= Fx = k(x ) = -ks(xx) 2 Fs = ks x = Fs -x ks 2 (x = x0 + 2mm)
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