A resistor of an unknown resistance is placed in an insulated container filled with 0.50 kg of water. A voltage source is connected in series with the resistor and a current of 1.2 amps flows through the resistor for 10 minutes. During this time, the temperature of the water is measured and the temperature change during this time is ΔT = 20.00 °C . (a) What is the resistance of the resistor? (b) What is the voltage supplied by the power supply? 

Note that the heat energy generated when a substance undergoes temperature change is given by $Q=mc\Delta T,$ where $$c is the specific heat capacity, $$m is the mass, $$ $\Delta T$ is the change in temperature. The specific heat capacity of water is $4186\frac{}{}j/kg°C.$

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a To find the resistance we first need to calculate the ... View the full answer