Question: Write an expression that will cause the following code to print Equal if the value of sensorReading is close enough to targetValue. Otherwise, print Not

Write an expression that will cause the following code to print

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". #include #include using namespace std: int main() { double targetValue = 0.3333: double sensorReading = 0.0: sensorReading = 1.0/3.0: if(/* Your Solution goes here */) { cout NestedLessLess "Equal" NestedLessLess end1: } else { cout NestedLessLess "Not equal" NestedLessLess end1: } return 0: }

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