Question: Answer the following questions: def report_size (n: str) -> str: # return small if n is between 0 and 20 # medium if n
Answer the following questions: def report_size (n: str) -> str: # return "small" if n is between 0 and 20 # "medium" if n is between 21 and 40 # "large" if n is 41 or greater if (len (n: int) == (0:20) -> str: This was the original question: def report_size(n: int) -> str: "Return 'small' if n is between 0 and 20 inclusive, 'medium' if n is between 21 and 40 inclusive, and 'large' if n is 41 or greater. Precondition: n >= 0 >>> report_size(4) 'small' >>> report_size(24) 'medium' >>> report_size(45) 'Large'
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Heres a python code def reportsizen int str if 0 The else statement provides a fallback option when neither the if condition nor the elif condition is ... View full answer
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