At a certain temperature, the equilibrium constant $K$ for the following reaction is $0\mathrm{.}0052$ :

$H_2(g)+C{l}_2(g)2HCl(g)$

Use this information to complete the following table.

Suppose a $47.$ L reaction vessel is filled with $1\mathrm{.}0$mol of $H_2$ and $1\mathrm{.}0$mol of $C{l}_2.$ What can you say about the composition of the mixture in the vessel at equilibrium?

There will be very little $H_2$ and $C{l}_2.$

There will be very little $HCl.$

Neither of the above is true.

What is the equilibrium constant for the following reaction?

Round your answer to $2$ significant digits.

$2HC{l}_{(g)}{H}_2(g)+C{l}_2(g)$

$K=$

What is the equilibrium constant for the following reaction?

Round your answer to $2$ significant digits.

$2H_2(g)+2C{l}_2(g)4HC{l}_{(g)}$

$K=$