Question: Br 2 (aq) + H 2 O(l) = HOBr(aq) + H + (aq) + Br - (aq) What happens to the equilibrium position when you

Br2 (aq) + H2O(l) = HOBr(aq) + H+ (aq) + Br- (aq)

What happens to the equilibrium position when you add potassium bromide?

What happens to the equilibrium position when you increase the pH.

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