Question: doubled 15 16 17 18 19 20 21 22 One Farad (F) is equal to: a. I volt /coulomb b. I coulomb/volt c. 1

doubled 15 16 17 18 19 20 21 22 One Farad (F) is equal to: a. I volt /coulomb b. I coulomb/volt c. 1 

doubled 15 16 17 18 19 20 21 22 One Farad (F) is equal to: a. I volt /coulomb b. I coulomb/volt c. 1 joule/coulomb d. I coulomb/joule In the figure, C-6 F, C-2 F and V-12 V. Calculate the charge on capacitor C a. 1210 C b. 2410 C c. 7210 C d. 610 C a 10.3 pc b. 14.5 pC c. 19.7 pc d. 16.8 PC A parallel-plate capacitor with plate's area of 26 cm and separation of 19.7 mm is charged by applying a voltage of 14 V across its ends. The total charge of the capacitor is If C-C-3 pF and C-C-2 pF, the equivalent capacitance between A and B is: a. 2.4 pF b. 3.7 pF c. 4.5 pF d. 5,8 pF a. 8x10 Ohm.m b. 24100 Ohm.m c. 3610 Ohm.m d. 72x10 Ohm.m a. does not obey conservation of energy law. b. obey Ohm's law. c. does not obey Ohm's law. d. does not obey conservation of charge law. V-12V The unit of conductivity is: a. N/C.A b. (Ohm.m) c. Ohm.m d. Ohm/m The electric field inside a cylindrical wire of radius 1.4 mm is 0.1 V/m. If the current in the wire is measured to be 17 A. The resistivity of the wire is: The table shows the current I(A) and potential difference V(v) through a device, the results determine that the device.... 41 The ideal battery in the figure has emf E- 6.0 V and the resistances are R-R-52 and R-402. The current in the resistance R, is: a. 0.9 A b. 1.5 A c. 0.4 A d. 1.0 A 3 | Page HP 00 C C 8=1 ww R V 1 2 4.5 3 4 VP I= ww 6.75 9 R ww

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

The detailed ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Programming Questions!