Consider the following function and closed interval.

$f(x)=x^3-3x+5,[-2,2]$

$Isf$ continuous $on$ the closed interval $-2,2?$

Yes, $it$ does not matter $iffis$ continuous $or$ differentiable; every function satisfies

the mean value theorem.

Yes, $fis$ continuous $on-2,2$ and differentiable $on(-2,2)$ since polynomials are

continuous and differentiable $onR.$

$No,fis$ not continuous $on-2,2.$

$No,fis$ continuous $on-2,2-2,2fis$ differentiable $on$ the open interval $(-2,2),$ find $f^{\text{'}}(x).(Ifitis$ not differentiable $on$

the open interval, enter DNE.$)$

$f^{\text{'}}(x)=$

Find $f(-2)$ and $f(2).(Ifan$ answer does not exist, enter DNE.$)$

$f(-2)=$

$f(2)=$

Find $\frac{f(b)-f(a)}{b-a}$ for $[a,b]=[-2,2].(Ifan$ answer does not exist, enter DNE.$)$

$\frac{f(b)-f(a)}{b-a}=$

Determine whether the mean value theorem can $be$ applied $tofon$ the closed interval

$-2,2.(Select$ all that apply.$)$

Yes, the Mean Value Theorem can $be$ applied.

$No,$ because $fis$ not continuous $on$ the closed interval $-2,2.$

$No,$ because $f-2,2No,$ because $\frac{f(b)-f(a)}{b-a}is$ not defined.

$If$ the mean value theorem can $be$ applied, find all values $ofc$ that satisfy the conclusion

$of$ the mean value theorem. $(Enter$ your answers $as$ a comma$-$separated list. $Ifit$ does

not satisfy the hypotheses, enter DNE$).$

$c=$