Consider the reaction $AkB$ where $-r_A=k(T)C_A^2.$ The reaction takes place

in an isobaric, adiabatic PFR with $F_{A_0}=22mo\frac{l}{s},C_{A_0}=1\mathrm{.}8M,$ and $T_0=180C.$

$k_{180C}$ was experimentally determined to be $4\mathrm{.}89*{10}^{-2}{M}^{-1}{s}^{-1},$ the enthalpy

change of reaction $H_{rxn,180C}=+16\frac{kJ}{\text{m}\text{o}\text{l}},$ and the activation energy $E_A=$

$114\mathrm{.}7\frac{kJ}{\text{m}\text{o}\text{l}}.$ Additionally, there is a non$-$participating species $C$ in the reaction

with ${}_C=0\mathrm{.}6$;

$C_{P_A}=133\frac{J}{\text{m}\text{o}\text{l}\text{K}}$ and $C_{P_C}=75\mathrm{.}38\frac{J}{\text{m}\text{o}\text{l}\text{K}}.$

Make a $($computer generated$)$ graph showing: a$)$ the conversion $x_A$ down the

length of the reactor and b$)$ the temperature down the length of the reactor up to

$x_A=0\mathrm{.}5.$