Question: Consider the vector function F(t) = (2 cost, 2 sint, 3), te [0, 2x], and its range C = {r(t) : te [0, 2x]). We

Consider the vector function F(t) = (2 cost, 2 sint, 3),

Consider the vector function F(t) = (2 cost, 2 sint, 3), te [0, 2x], and its range C = {r(t) : te [0, 2x]). We show that C is the circle in the plane with equation z = 3, with centre c = (0,0,3) and radius 2

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