Question: COS 5x 2 sin (2) cos-0 2 = Since it's something times something, we can break our equation into smaller simpler equations: 2 sin

COS 5x 2 sin (2) cos-0 2 = Since it's something times

COS 5x 2 sin (2) cos-0 2 = Since it's something times something, we can break our equation into smaller simpler equations: 2 sin () 5x = 0 OR cos sin () 5x = = 0 OR cos 2 First, we'll solve sin = 0. Which angles make have a sine of O? sin 0 = 0 for 0 = [Select] That tells us that X [Select] 2 Now we just multiply both sides of the equation by 2 to get x by itself and then pick out the solutions with 0 < x

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