Explanation Concentration Ca(NO 3 ) 2 = 0.3 M volume Ca(NO 3 ) 2 = 0.1 L
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Question:
Explanation
Concentration Ca(NO3)2 = 0.3 M
volume Ca(NO3)2 = 0.1 L
moles Ca(NO3)2 = (Concentration Ca(NO3)2) * (volume Ca(NO3)2)
moles Ca(NO3)2 = (0.3 M) * (0.1 L)
moles Ca(NO3)2 = 0.03 mol
final volume = 0.1 L + 0.2 L = 0.3 L
final concentration of Ca(NO3)2 = (moles Ca(NO3)2) / (final volume)
final concentration of Ca(NO3)2 = (0.03 mol) / (0.3 L)
final concentration of Ca(NO3)2 = 0.1 M
Similarly, final concentration of NaF = 0.04 M
Reaction quotient, Qsp = [Ca2+][F-]2
Qsp = (0.1 M) * (0.04 M)2
Qsp = 1.6 x 10-4
Since Qsp > Ksp, therefore, precipitate will form.
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