Given a simple Project like the one pictured above Optimistic Most Likely Pessimist Times were assessed and Path Means and Path Standard Deviations were calculated For Path 1 2 5 we have a Path Mean 30 and a Path Standard Deviation 5 For Path 1 3 4 5 we have a Path Mean 32 and a Path Standard Deviation 4 Determine both the Probability that Path 1 2 5 will finish in 32 Days or Less and the Probability that the Project will finish in 32 Days or Less Question 5 options 0 655421697 0 327710848 0 84134474 0 65067307 0 964069734 0 925449956 0 986096601 0 974042129 Given a simple Project like the one pictured above Optimistic Most Likely Pessimist Times were assessed and Path Means and Path Standard Deviations were calculated For Path 1 2 5 we have a Path Mean 30 and a Path Standard Deviation 5 For Path 1 3 4 5 we have a Path Mean 32 and a Path Standard Deviation 4 Determine both the Probability that Path 1 2 5 will finish in 32 Days or Less and the Probability that the Project will finish in 32 Days or Less Question 5 options 0 655421697 0 327710848 0 84134474 0 65067307 0 964069734 0 925449956 0 986096601 0 974042129

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Question: Given a simple Project like the one pictured above. Optimistic / Most Likely / Pessimist Times were assessed and Path Means and Path Standard Deviations

Given a simple Project like the one pictured above. Optimistic / Most Likely / Pessimist Times were assessed and Path Means and Path Standard Deviations were calculated. For Path 1-2-5 we have a Path Mean = 30 and a Path Standard Deviation = 5. For Path 1-3-4-5 we have a Path Mean = 32 and a Path Standard Deviation = 4. Determine both the Probability that Path 1-2-5 will finish in 32 Days or Less and the Probability that the Project will finish in 32 Days or Less.

Question 5 options:

	0.655421697 : 0.327710848
	0.84134474 : 0.65067307
	0.964069734 : 0.925449956
	0.986096601 : 0.974042129

Question 5 options:

	0.655421697 : 0.327710848
	0.84134474 : 0.65067307
	0.964069734 : 0.925449956
	0.986096601 : 0.974042129

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