Question: Given that the acceleration vector i s a ( t ) = ( - 9 c o s ( 3 t ) ) i +

Given that the acceleration vector isa(t)=(-9cos(3t))i+(-9sin(3t))j+(-t)k, the initial velocity isv(0)=i+k, and the initial position vector isr(0)=i+j+k,compute :
A. The velocity vector v(t)=
i+
j+
k
B. The position vector r(t)=
i+
j+,k
Given that the acceleration vector i s a ( t ) =

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