Question: I'm following the attached lecture notes for proving Convergence almost everywhere implies convergence in measure with Egoroff's theorem. Convergence almost everywhere implies convergence in mea-

I'm following the attached lecture notes for proving "Convergence almost everywhere implies convergence in measure" with Egoroff's theorem.

I'm following the attached lecture notes forI'm following the attached lecture notes forI'm following the attached lecture notes for
Convergence almost everywhere implies convergence in mea- sure. Theorem 0.2. If fn - f a.e. and u(X ) 0, there exists N such that If (x) - fn(x)| N and all a: E E. So, for n > N, |f(:1:) fn(:1:)| can be greater than 6 only on (A \\ E) U (X \\ A). This means that M({56 \\ \\Mm) f(93)| > 6}) S MAW-*7) +M(X\\A) N. E] Egoroff's theorem (pointwise convergence is nearly uniform. Theorem 0.1. Suppose M(X ) 0, there exists a measurable subset E C X with u(X \\ E) f uniformly on E

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