In Class Example $2.$

The glue seams can withstand a maximum shear stress of $1\mathrm{.}5$ MPa and the wood a maximum allowable shear stress of $3$ MPa $.$ Find the maximum allowable shear force V in the beam $($a$)$ for the wood, $($b$)$ at glue joint $B,$ and $(c)$ at glue joint $D.$

Answers:

$I=\frac{1}{12}(0\mathrm{.}15)({0\mathrm{.}25}^3)-\frac{1}{12}(0\mathrm{.}1)({0\mathrm{.}15}^3)$

$=0\mathrm{.}1671875{10}^3{m}^4$

$V_{\text{a}\text{l}\text{l}\text{o}\text{w}\text{e}\text{d}}=28\mathrm{.}157kN,$ on the neutral axis where $Q$ is maximum and $t=0\mathrm{.}05m.$

$V_{\text{a}\text{l}\text{l}\text{o}\text{w}\text{e}\text{d}}=16\mathrm{.}7kN$ for the glue seam $atB$

and $t=0\mathrm{.}05m.$