In JAVA Please, thanks.

42.35 PRACTICE: Arrays : Grouping into ranges A publisher may allow a reader to select a subset of chapters to purchase. Given 15 integers that are 0 or 1 indicating whether or not to include chapters 1 to 15 , output the selection using shorthand for ranges of 3 or more (11,12,13 becomes 11-13). If the input is 111101 011011100 , the output should be: 1-4 689 11-13. If no chapters are selected, output: None. For simplicity, follow every term including the last by one space (and end with newline). Hints: - This problem is hard. Start by creating a for loop that just prints the selected chapters one by one, without shorthands for ranges. Your program will pass a few test cases. - Next, extend the loop body to handle the case for a range of 3. Use an if statement to lookahead from index i to i+1 and i+2. If all three elements are 1's, print the range. Be careful to only do the lookahead if the current i is 13 or less. If the current index is 14 (or 15 ), there's no need to lookahead; the range can't be 3 or more because only 15 chapters exist. - If your loop body printed a range like 2-4, don't forget to update your loop's index i to be 4 (don't leave it at 2). - One you get the above working, then use a nested while loop to detect even larger ranges, such as 2-7. And don't forget to update the for loop index i to the detected range end. - Use a boolean variable, initialized to false, and in your for loop set it to true if any chapter is selected. After your for loop above, if the variable is still false, print "None ". Main.java Load default template... import java.util.Scanner; public class Main \{ public static void main (String[] args) \{ Scanner scnr = new Scanner(System.in); boolean[] chptList = new boolean[16]; // Valid chapters are 1 -15. 1 means include, 0 exclude. Element unus int includeChpt; int i,j; // Get the chapter selections for ( i =1; i =15;++i){ includeChpt = scnr. nextInt (); if (includeChpt==1)\{ chptList [i]= true; \} Main.java Load default template