$($Investigation$)$ In a computer system, the instruction cache $($I$-$cache$)$ has a miss rate of $3\%$ and a miss

penalty of $80$ cycles, while the data cache $($D$-$cache$)$ has a miss rate of $5\%$ and a miss penalty of $120$ cycles.

If load and store instructions constitute $40\%$ of all instructions executed, calculate the miss cycles for both

I$-$cache and D$-$cache respectively.

$2\mathrm{.}4$ cycles, $6$ cycles

$=>,2\mathrm{.}4$ cycles, $2\mathrm{.}4$ cycles

$2\mathrm{.}4$ cycles, $4\mathrm{.}8$ cycles

x $6$ cycles, $2\mathrm{.}4$ cycles

please explain why the second option is correct