Net Force = F1+F2 Now, let's calculate the forces using the given values: 1.650x10 C1.65010-C (0.06...

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Net Force = F1+F2 Now, let's calculate the forces using the given values: 1.650x10 C1.650×10-C (0.06 m)² F1 = (8.988 x 10° N m²/C²). E = 3.422 N F2= (8.988 × 10º N·m²/C²) = 0.483 N Net Force = F1 + F2 . = 3.422 N + 0.483 N = 3.905 N 1.650×10-C-1.650x10-6C| (0.22) Therefore, the force on the charge located at 16.00 cm is 3.905 N Net Force = F1+F2 Now, let's calculate the forces using the given values: 1.650x10 C1.650×10-C (0.06 m)² F1 = (8.988 x 10° N m²/C²). E = 3.422 N F2= (8.988 × 10º N·m²/C²) = 0.483 N Net Force = F1 + F2 . = 3.422 N + 0.483 N = 3.905 N 1.650×10-C-1.650x10-6C| (0.22) Therefore, the force on the charge located at 16.00 cm is 3.905 N

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Given 91 57 C 57 x 106 C 92 57 C 57 x 106C r 9 cm 009 m Using Coulombs Law k 91 92 p2 F F F F F ... View the full answer