Predecessor NAME A B D DURATION 3 4 2 6 5 4 7 3 11 A,B E F G DE F F H I Above is the activity table of the project. For the given project, find the critical path and the project duration A-B-C-E-H-I, 26 B-C-F-H, 16 None of the above B-C-E-G, 23 B-C-F-I, 21 Expected project time is the sum of the expected times of the critical path activities. Project variance is the sum of the critical path activities' variances The expected project time is assumed to be normally distributed (based on central limit theorem). Let's assume that we have a project which has: * Expected project time of 35 * Project variance of 14 What is the probability that the project can be finished in 39 weeks? around 85% None of the above around 65% around 95% o around 75% 3 NAME DURATION CRASHED Duration PREDECESSOR COST CRASH COST A 3 2 1000 1500 B 4 3 1500 2500 2 1 1000 1800 D 6 4 A,B 1000 2800 E 5 3 2500 3000 F 3 2 D 2000 2500 G 8 7 DE 1500 2750 H 4 2 E 2000 3000 3 For the given the project, manually crash the model and answer to the below question. The company wants to finish this project in 15 weeks. Find the minimum expediting cost. None of the above 2500 2000 2250 2800