Problem #2 R = 500 92 R, = 3k R = lk 92 R=75 92 R=...

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Problem #2 R = 500 92 R, = 3k R = lk 92 R=75 92 R= 100 22 R = 220 2 b Note on resistance units: If you are familiar with SI units, then a multiplier is prefixed to the unit. For example, "1 k" represents 1000 92. In electronics, you often see the multiplier as a suffix to the number, such as "Ik 2" or "IK 2". It is also equal to 1000 $2. Either way is fine for this course. R= 150 2 R100 S2 Round your final numeric answers to two decimal places. For units, express resistance in ohms (22), voltage in volts (V), current in amperes (A), and power in watts (W). For each part below, explain the analysis that you used to derive your equations. If you show no work, then you get no credit. a) What is the equivalent resistance Reg of the original circuit between points a and b? To answer Parts (b) through (e), assume the positive side of a 100 volt DC voltage supply is connected to point a and the negative side of the supply is attached to point b. b) What is the total current flowing into point a? c) What is the voltage drop across the 220 22 resistor? d) What is the current in the 759 resistor? e) What is the amount of power dissipated by resistor R7? f) Write a Python script based on your equations to perform the actual numeric calculations. Each section of the script should have a comment that indicates which question it is solving. Note: The grader will run your script to see if it produces the same answers you wrote for Parts (a) through (e). R # R 36 HR J R7 = b) R27 41 are insernes > R R36 + R7, 500 + 165.789 + 100 = 765.789 r Reg Regs R-7X R8 R-7 + R18 100+ V R are 18 = 470.474& IT in paralel a 765.78 x 1220 765.78 +1220. Reg b 000) Vs Rea ITS V 3 934262.58 1985.789 100 5 Reg 470.474 = 0.2125 A ITS 0.2125 A Problem 2 a) a R & Rd are M series R8 = R + R8 = 1000 +228 = 1220 RS & R6 are in series = RS6 RS + R6 = 3 R3 R4 are in Series R34 = R3+R 4 = 3000 + 150 = 3150 R18 100+ 75 1752 Y R2 R34 R34 R 56 are in & R36 = R34 11 Rs6 = R7 Paralel R34XR56 R34 R56 165.789 () 0 m R R according Udropps a Rp mu RS R3 Ro Fu Ry 100 Voltage in same branchs above becaus it is parallec Circuit Ri R8 b lo in same betwe aub mall 3 loo to voldag devicher formula & R8 Ut R+R8 220 1000 + 220 x 100 22000 -18 032 1220 V Udrop R8 = 18.032v/ d) loov 5. 12t Curren R2-7 7657675 Fx (R+R) = 100 I = 0.0819 A 12 = IT- 11 = 0.2125 -0.0819 = 0.13058 A fi in Series Current B + Currut devicer vale acevos R Rr@[2 m s Fur 13= 12 (R3+R4) 13 < 0.12376 A R3 Same says: RE M (2+R4) +RS+R6) R4 and cure cus I shous; Ry 12 3150 3325 RS (753) in same Series Or Some 13 I RAT 0.12376 A e) Carren for R7+ I = 013058 A R7 = R7122= (0.130581 100+ P75 170511 W Problem #2 R = 500 92 R, = 3k R = lk 92 R=75 92 R= 100 22 R = 220 2 b Note on resistance units: If you are familiar with SI units, then a multiplier is prefixed to the unit. For example, "1 k" represents 1000 92. In electronics, you often see the multiplier as a suffix to the number, such as "Ik 2" or "IK 2". It is also equal to 1000 $2. Either way is fine for this course. R= 150 2 R100 S2 Round your final numeric answers to two decimal places. For units, express resistance in ohms (22), voltage in volts (V), current in amperes (A), and power in watts (W). For each part below, explain the analysis that you used to derive your equations. If you show no work, then you get no credit. a) What is the equivalent resistance Reg of the original circuit between points a and b? To answer Parts (b) through (e), assume the positive side of a 100 volt DC voltage supply is connected to point a and the negative side of the supply is attached to point b. b) What is the total current flowing into point a? c) What is the voltage drop across the 220 22 resistor? d) What is the current in the 759 resistor? e) What is the amount of power dissipated by resistor R7? f) Write a Python script based on your equations to perform the actual numeric calculations. Each section of the script should have a comment that indicates which question it is solving. Note: The grader will run your script to see if it produces the same answers you wrote for Parts (a) through (e). R # R 36 HR J R7 = b) R27 41 are insernes > R R36 + R7, 500 + 165.789 + 100 = 765.789 r Reg Regs R-7X R8 R-7 + R18 100+ V R are 18 = 470.474& IT in paralel a 765.78 x 1220 765.78 +1220. Reg b 000) Vs Rea ITS V 3 934262.58 1985.789 100 5 Reg 470.474 = 0.2125 A ITS 0.2125 A Problem 2 a) a R & Rd are M series R8 = R + R8 = 1000 +228 = 1220 RS & R6 are in series = RS6 RS + R6 = 3 R3 R4 are in Series R34 = R3+R 4 = 3000 + 150 = 3150 R18 100+ 75 1752 Y R2 R34 R34 R 56 are in & R36 = R34 11 Rs6 = R7 Paralel R34XR56 R34 R56 165.789 () 0 m R R according Udropps a Rp mu RS R3 Ro Fu Ry 100 Voltage in same branchs above becaus it is parallec Circuit Ri R8 b lo in same betwe aub mall 3 loo to voldag devicher formula & R8 Ut R+R8 220 1000 + 220 x 100 22000 -18 032 1220 V Udrop R8 = 18.032v/ d) loov 5. 12t Curren R2-7 7657675 Fx (R+R) = 100 I = 0.0819 A 12 = IT- 11 = 0.2125 -0.0819 = 0.13058 A fi in Series Current B + Currut devicer vale acevos R Rr@[2 m s Fur 13= 12 (R3+R4) 13 < 0.12376 A R3 Same says: RE M (2+R4) +RS+R6) R4 and cure cus I shous; Ry 12 3150 3325 RS (753) in same Series Or Some 13 I RAT 0.12376 A e) Carren for R7+ I = 013058 A R7 = R7122= (0.130581 100+ P75 170511 W