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Limiting Reactants In the above reactions we assumed that if a quantity of one reactant was given and there was enough of the other reactant or reactants. Here you are given the quantity of each reactant. The quantities would not be in exact amounts for all the reactants to be used up. One reactant would be in excess and the other would be limited. Method: 1. Calculate how much of product (in terms of one product) would each given quantity of reactant produce if there was no shortage of the other reactant. 2. Whichever produces less of the specific product, is the limiting reactant. 3 . The amount of product would be determined by the limiting reactant. Mole to Mole Limiting Reactant questions: 2KOH(aq)+H2SO4(aq)KSO4(aq)+2H2O(I) 1. If 13.3 moles of H2SO4 is reacted with 27.8 moles of KOH then how many moles of water can be produced? A. What is your limiting reactant? B. What is your excess reactant? Mass To Mass Limiting Reactant Questions and Theoretical Yield 2KOH(aq)+H2SO4(aq)K2SO4(aq)+2H2O(l) I. If 207.61g of KOH reacts with 205.97g of H2SO4 then: A. What is the maximum mass of water that can be produced (theoretical yield)? B. What is your limiting reactant? C. What is your excess reactant