Suppose 22 g of C3H8 gas was compressed into a 425 ml steel cylinder at a temperature of 25C. What pressure in atm would the gas exert on the walls of the cylinder? Select the proper set-up for this calculation. - Given: PV= nRT where R = 0.0821 liter atm / mole K - 1 atm = 760 torr, Kelvin = C + 273, 1 L = 1000 ml Like # 6.48 O (0.50)(0.0821)(298) (425) O (22)(0.0821)(25) = (425) O (22)(0.0821)(298) + (0.425) (0.50)(0.0821)(25) (0.425) O (0.50)(0.0821)(298) (0.425) 7

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The correct setup of the calculation according to the ideal gas law PV nRT i... View the full answer