Question: Suppose you have a four-activity sequential process. Throughput capacities are shown in parentheses: Task 1 (3) ---> Task 2 (4) ---> Task 3 (2) --->

Suppose you have a four-activity sequential

Suppose you have a four-activity sequential process. Throughput capacities are shown in parentheses: Task 1 (3) ---> Task 2 (4) ---> Task 3 (2) ---> Task 4 (10). No buffers exist between tasks, so an upstream task must wait if the downstream task is busy. Use this information to answer the next 2 questions. What is the actual throughput rate out of task 4? O Less than 1 O Greater than or equal to 1 but less than 2 O Greater than or equal to 2 but less than 3 O Greater than or equal to 3 but less than 4 O Greater than or equal to 4 but less than 5 O Greater than or equal to 5 What is the utilization for task 1? 0% Greater than 0% but less than 10% O Greater than or equal to 10% but less than 25% Greater than or equal to 25% but less than 50% O Greater than or equal to 50% but less than 75% O Greater than or equal to 75% but less than 100% O 100%

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