Question: t= expected time =(a+4m+b)/6 variance =((ba)/6)2 a= optimistic time b= pessimistic time m= most likely Inlude two decimal points. Answer: Expected time = ; Variance

t= expected time =(a+4m+b)/6 variance =((ba)/6)2t= expected time =(a+4m+b)/6 variance =((ba)/6)2t= expected time =(a+4m+b)/6 variance =((ba)/6)2

t= expected time =(a+4m+b)/6 variance =((ba)/6)2 a= optimistic time b= pessimistic time m= most likely Inlude two decimal points. Answer: Expected time = ; Variance = Now that you have found the expected time and variance of activity G answer the following question: (B) Suppose this project has a single critical path (based on precedence relationships not shown here) and the critical path is ABEFH. (i) Describe the probability distribution for the total project time. (Tell the center (mean), shape (distribution name), and spread (standard deviation).) Keep only one decimal point. Answer: Shape = ; center = ; spread = Based on what you got in previous questions, answer the two questions below: (ii) Find the probability that the project will take more than 26 hours. (Give answer to the nearest percent) Steps: 1. Find z value : z=(xmean)/standard deviation; where x is the target (26) 2. Find the probability or area under the curve on z-table for z-value found in step 1. 3. Subtract the number from 1 as we lok for the values greater than 26. (iii) Suggest a due date that gives the project a 88% chance of on-time completion. hours. (Give answer to one decimal.) Steps: 1. Find z score of 0.88 (look inside the z table for 0.88 and read corresponding first column and first row) and call it z _ 0.88. 2. Calculate the target (x) using: x= mean +z0.88 standard deviation

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