The liquid phase reaction is run in a batch reactor. The following data are valid.rA $=-$kCAEA$=41\mathrm{.}87\backslash$times $103$ kJ$/$kmole $=1050/3=2/30$k $(298$ K$)=1\mathrm{.}7\backslash$times $10-4$ s$-1(298)=167\mathrm{.}5\backslash$times $103/$Cp $=4\mathrm{.}19$ kJ$/$kgKV $=0\mathrm{.}5$ m$3$CP and can be assumed to be constant. The tank reactor is made of steel and weighs $800$ kg$,$ Cp$-$steel $=502\mathrm{.}4$ kJ$/$kgK$.$Calculate the conversion and the reactor temperature as a function of the reaction time if the initial temperature at time t$=0$ is $298$ K and under the condition that the reactor is well insulated that the temperature losses to the environment may be neglected. What reaction time is required for a conversion of $95\%?$