The reaction between HCI and NaOH is represented below. When equal volumes of 1.00 M NaOH...

 

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The reaction between HCI and NaOH is represented below. When equal volumes of 1.00 M NaOH and 1.00 M HCI are mixed, 57.1 kJ of heat is released. What would AH be if 2.00 M HCI and 2.00 M NaOH is used instead of 1.00 M? HCl(aq) + NaOH(aq)- NaCl(aq) + H2O(l) =-57.1 kJ/mol The reaction between HCI and NaOH is represented below. When equal volumes of 1.00 M NaOH and 1.00 M HCI are mixed, 57.1 kJ of heat is released. What would AH be if 2.00 M HCI and 2.00 M NaOH is used instead of 1.00 M? HCl(aq) + NaOH(aq)- NaCl(aq) + H2O(l) =-57.1 kJ/mol

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Solution Calculating the change in energy ... View the full answer