Question: We have used Raoult's law to obtain the expression for the freezing point shift of a solution: RT;XB Afus HAm If the activity of

We have used Raoult's law to obtain the expression for the freezing

We have used Raoult's law to obtain the expression for the freezing point shift of a solution: RT;XB Afus HAm If the activity of the solvent is given instead by aa = k XA and the vapor pressures of the pure solvent and solute are P and P, what is the new equation for AT; in terms of the mole fraction of solute? 21n kA O AT RT; Afus HAm RT;2(In kA- XB) Afus HAm RT; In kA Afus HAm 2 RT;XXB AT Afus HAm RT;2(In kA- XB) O AT fus Hm RT;XAXB AT = Afus Hm

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