Question: A 0.42 kg shuffleboard disk is initially at rest when a player uses a cue to increase its speed to 4.2 m/s at constant acceleration.

A 0.42 kg shuffleboard disk is initially at rest when a player uses a cue to increase its speed to 4.2 m/s at constant acceleration. The acceleration takes place over a 2.0 m distance, at the end of which the cue loses contact with the disk. Then the disk slides an additional 12m before stopping. Assume that the shuffleboard court is level and that the force of friction on the disk is constant. What is the increase in the thermal energy of the disk-court system?
(a) For that additional 12 m and
(b) For the entire 14 m distance?
(c) How much work is done on the disk by the cue?

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a During the final d 12 m of motion we use K U KU fkd where v fid37 J 1m 0 mv 42 ms This gives fx ... View full answer

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