Question: Use the data in Appendix 2B and the fact that, for the half-reaction F 2 (g) + 2 H + (aq) + 2 e
Use the data in Appendix 2B and the fact that, for the half-reaction F2(g) + 2 H+(aq) + 2 e– → 2 HF(aq), E° = 13.03 V, to calculate the value of Ka for HF.
2B STANDARD POTENTIALS AT 25 C Potentials in Electrochemical Order Reduction half-reaction Strongly oxidizing H4XeO6+ 2 H+2 e XeO3 + 3 HO F2 e 2 F- O3 + 2 H+ 2 eO + HO SO8 +2e 2 SO4- Ag+ +e Agt Co+ + e Co+ HO2 + 2 H Au + e Pb+ + 2 e + 2e 2 HO Au Pb+ 2 HClO + 2 H+2 e Cl + 2 HO Cee Ce+ Mn+ + 4HO 2 HBrO + 2 H+2 e Br2 + 2 HO MnO4 + 8 H+ + 5 e Mn+ + e Mn+ Au+ + 3 e Au Cl + 2 e 2 CI CrO7- + 14 H+ + 6 e 2 Cr+ + 7 HO O3+ HO + 2e O + 2 OH 2HO O + 4H+ + 4e E/V +3.0 +2.87 +2.07 +2.05 +1.98 +1.81 +1.78 +1.69 +1.67 +1.63 +1.61 +1.60 +1.51 +1.51 +1.40 +1.36 +1.33 +1.24 +1.23 Reduction half-reaction NO3 + HO + 2e NO+ 2 OH Ti + e Ti+ 2H+ +2 e Fe+ + 3 e H Fe O + HO + 2e HO + OH Pb+ + 2 e pb In e In Sn+ + 2 e AgI+ e Sn Ag + I Ni Ni+ + 2e V+ + e V+ Co+ + 2e In+ + 3 e Tl +e Tl Co In PbSO4 + 2 e Pb + SO4- Ti+ + e Ti+ In++eIn+ Cd+ + 2 e Cd Cr+ + eCr+ Fe+ + 2 e Fe E/V +0.01 0.00 0, by definition -0.04 -0.08 -0.13 -0.14 -0.14 -0.15 -0.23 -0.26 -0.28 -0.34 -0.34 -0.36 -0.37 -0.40 -0.40 -0.41 -0.44
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