Question: Ag ( aq ) + + e - - > Ag ( s ) Eor = 0 . 8 0 V Cr ( aq )

Ag(aq)++ e--> Ag(s) Eor =0.80 V
Cr(aq)3++3e--> Ni(s) Eor =-0.74 V
If you were to prepare a galvanic cell involving silver and chromium electrodes,
a) Which half reaction is undergoing oxidation? Explain your rationale. (0.5 mark)
b) Which substance is the cathode? Explain your rationale. (0.5 mark)
c) Which direction should electrons flow? In your answer, specify the anode and cathode and the direction of electron flow. (0.5 mark)
d) Suggest a solution that could be used for the salt bridge. Explain your rationale. (0.5 mark)
e) Write the net ionic equation for the spontaneous reaction for the galvanic cell. (1 mark)Question 7(5 points)
Ag(aq)++e-Ag(s),Ero=0.80V
Cr(aq)3++3e-Ni(s),Ero=-0.74V
If you were to prepare a galvanic cell involving silver and chromium electrodes,
a) Which half reaction is undergoing oxidation? Explain your rationale. (0.5 mark)
b) Which substance is the cathode? Explain your rationale. (0.5 mark)
c) Which direction should electrons flow? In your answer, specify the anode and
cathode and the direction of electron flow. (0.5 mark)
d) Suggest a solution that could be used for the salt bridge. Explain your rationale.
(0.5 mark)
e) Write the net ionic equation for the spontaneous reaction for the galvanic cell. (1
mark)
e) Showing your work, calculate the cell potential for a spontaneous reaction for this
galvanic cell. (2 marks)
 Ag(aq)++ e--> Ag(s) Eor =0.80 V Cr(aq)3++3e--> Ni(s) Eor =-0.74 V

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