Question: Consider the following sub _ module _ verilog code: module sub - module - verilog ( input A , B , output wire M ,

Consider the following sub_module_verilog code:
module sub-module-verilog (input A, B, output wire M, N,S);
Assign MA~^B;
Assign NA & ~B;
Assign S = ~A & B;
endmodule
Consider the following main_module_verilog code:
module main-module-verilog (input wire [2:0] A, B,
output wire X, Y, Z);
wire so, s1, s2,53,54,55,56,57,58;
sub-module-verilog eq_bito (.A (A[0]), B(B[0]),.M(50),
.N(s1), S(s2));
sub-module-verilog eq_bit1(.A(A[1]), B(B[1]),.M(S3),
.N(s4),.S(s5));
sub-module-verilog eq bit2(.A (A[2]),.B (B[2]),.M(56),
.N(s7),.S(58));
assign X so & s3 & s6;
assign Ys7|(s6 & s4)
|
(s6 & s3 & s1);
assign Z s8|(s6 & s5)
endmodule
|
(s6 & s3 & 52);
The module described above represents
None of the above
3-bit magnitude comparator
3-bit parity generator

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