Question: Determine the limiting reactant. Express your answer as a chemical formula. Lead(II) ions can be precipitated from solution with KCl according to the following reaction:

Determine the limiting reactant. Express your answer as a chemical formula.

Lead(II) ions can be precipitated from solution with KCl according to the following reaction: Pb2+(aq) + 2KCI(aq) -+ PbCl2 (s) + 2K+ (aq) When 28.3 g KCl is added to a solution containing 25.5 g Pb-+, PbCle (s) forms. The solid is filtered and dried and found to have a mass of 29.6 g

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