Find all the numbers that can be written as the product of two even square numbers in succession and print them in increasing order. (For example, 64 is the first number that should be in your output as 4x16=64, where 4 and 16 are two even square numbers in succession). The user should specify how many such numbers they want to print. For each number found the program should also check/state whether the number found was odd or even and print this information too.

 

Transcribed Image Text:

#include <iostream> #include <cmath> // Function to calculate the nth term of the sequence double calculateTerm(int n, int a, int b) { return (a* std:: pow(n, 3))+ (b * n); } //Function to check if a term is a factor of a given number bool isFactor (int term, int number) { return (number % term) } int main() { int choice; == std::cout << "Options: \n"; std::cout << "1. Find a limited number of terms of the sequence std::cout << "2. Find a term in a position and check if it is a std::cout << "Enter your choice (1 or 2): "; std::cin >> choice; if (choice == 1) { // Option 1: Find a limited number of terms int a, b, maxTerms; std::cout << "Enter the value of 'a': "; std::cin >> a; #include <iostream> #include <cmath> // Function to calculate the nth term of the sequence double calculateTerm(int n, int a, int b) { return (a* std:: pow(n, 3))+ (b * n); } //Function to check if a term is a factor of a given number bool isFactor (int term, int number) { return (number % term) } int main() { int choice; == std::cout << "Options: \n"; std::cout << "1. Find a limited number of terms of the sequence std::cout << "2. Find a term in a position and check if it is a std::cout << "Enter your choice (1 or 2): "; std::cin >> choice; if (choice == 1) { // Option 1: Find a limited number of terms int a, b, maxTerms; std::cout << "Enter the value of 'a': "; std::cin >> a;

Answer rating: 100% (QA)

To solve this problem we need to generate numbers that are the product of two even square numbers in ... View the full answer