In a computer system, assume that main memory accesses take $75$ ns and that memory accesses are one third of all instructions. The following table shows data for caches attached to each of two processors, Pi and P$2.$A$.$ Assuming a base CP$|$ of $1\mathrm{.}0$ for both processors without any memory stalls, thetotal CPI for P$,$ is$-$ Round the result with two digits afterdecimal points. $($total CP$|=$ base CP$|+$ data memory stall CP$|+$ instructionmemory stall CPI$)$B$.$ Total CP$|$ for P$2$ is$.$ Round the result with two digits afterdecimal points. $($total CP$|=$ base CP$|+$ data memory stall CP$|+$ instructionmemory stall CPI$)$C$.$ In order to increase the number of instructions being executed by $10\%,$ we add a second$-$level cache for P$1.$ If the second$-$level cache has ons hit time, its missrate must bepercent. Round the result with two digits afterdecimal points.