Question: please help and explain part c An automatic lathe produces rollers for roller bearings, and the process is monitored by statistical process control char The

please help and explain part c An automatic lathe
please help and explain part c An automatic lathe
please help and explain part c An automatic lathe
please help and explain part c
An automatic lathe produces rollers for roller bearings, and the process is monitored by statistical process control char The central line of the chart for the sample means is set at 8.50 and for the mean range at 0.34mm. The process is in control, as established by samples of size 5 . The upper and lower specifications for the diameter of the rollers are (8.50+0.35) and (8.500.35)mm, respectively. Click the icon to view the table of factors for calculating three-sigma limits for the x-chart and R-chart. a. Calculate the control limits for the mean and range charts. The UCL LR equals mm and the LCLR equals mm. (Enter your responses rounded to two decimal places.) The UCLx equals mm and the LCLx equals mm. (Enter your responses rounded to two decimal places.) b. If the standard deviation of the process distribution is estimated to be 0.18mm, is the process capable of meeting specifications? Assume four-sigma quality. A. Yes, because Cpk is greater than the critical value of 1.33. B. Yes, because Cpk is less than the critical value of 1.33. C. No, because Cpk is greater than the critical value of 1.33. D. No, because Cpk is less than the critical value of 1.33. c. If the process is not capable, what percent of the output will fall outside the specification limits? (Hint Refer to the standard normal table.) \%. (Enter your response rounded to two decimal places. Type N if there is no solution.)

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