Question: The rectangles in the graph below illustrate a left endpoint Riemann sum for at) = (15 /ac) on the interval [2,6]. The value of this

 The rectangles in the graph below illustrate a left endpoint Riemannsum for at) = (15 /ac) on the interval [2,6]. The valueof this left endpoint Riemann sum is - , and this Riemann
sum is an overestimate of v Q) the area of the regionenclosed by y = f(ac), the xaxis, and the vertical lines x= 2 and x = 6. Left endpoint Riemann sum for y

The rectangles in the graph below illustrate a left endpoint Riemann sum for at) = (15 /ac) on the interval [2,6]. The value of this left endpoint Riemann sum is - , and this Riemann sum is an overestimate of v Q) the area of the region enclosed by y = f(ac), the xaxis, and the vertical lines x = 2 and x = 6. Left endpoint Riemann sum for y = (15 /x) on [2, 6] The rectangles in the graph below illustrate a right endpoint Riemann sum for f (w) = (15 /ac) on the interval [2,6]. The value of this right endpoint Riemann sum is - , and this Riemann sum is an underestimate of v 9 the area of the region enclosed by y = f (.73), the Xaxis, and the vertical lines x = 2 and x = 6. Right endpoint Riemann sum for y = (15 / m) on [2,6] Ni _%= Consider the function f(x) = 6 - |x| defined on [-6, 6]. (a) Compute the left Riemann sum L4. L4 = (b) Compute the right Riemann sum R4. RA = (c) Compute the average value of L4 and R4. Average value (d) Compute the area under the graph of f. Area (e) Compare the two values found in (c) and (d). The average value is ? the area

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