If $F(x)={\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{dx}{sech(2x)[2-sinh(2x)]}$ and $F(ln2)=\frac{3}{2}ln2,$ then $F(0)=?$

$($a$)ln\sqrt[\phantom{2}]{2}$

$($b$)\sqrt[\phantom{2}]{2}$

$($c$)0$

$($d$)ln(\frac{\sqrt[\phantom{2}]{2}}{2})$

$($e$)\frac{\sqrt[\phantom{2}]{2}}{2}$