Question: QUESTION 25 25. The critical path for the network activities shown below is with duration Activity Duration V W 10 8 2 4 Immediate Predecessors

QUESTION 25 25. The critical path for the network

QUESTION 25 25. The critical path for the network activities shown below is with duration Activity Duration V W 10 8 2 4 Immediate Predecessors - V V x WY Ir Z a. V-W-Z: 23 b. V-X-Z; 17 V.X-Y-Z; 21 V-X-W-Y-Z: 29 d Cenone of the above QUESTION 26 26. Activity D on a PERT network has an optimistic duration of 3 days, a most likely duration of 5 days and a pessimistic duration of 13 days. What is the expected duration of activity D? Formula: Expected Activity time: t = (a + 4m +b)/6 a. 5 days b. 6 days Oc 7 days 10 days d. e. 12 days QUESTION 27 27. A project being analyzed by PERT has an identified critical path. If the estimated time along the critical path is 214 days with a variance of 100 days, the probability that the project completion date will exceed 224 days, is...... (Normal distribution curve values are given below) Formulae: Standard Deviation of Activity time = SQRT (variance) Z value = (X - mean) /Std Dev z Value 2.5 Cumulative Probability under Normal Curve upto z 0.5000 0.5398 0.6915 0.8413 0.9332 0.9773 0.9938 0.9987 a. near zero 6.0.0668 0.1587 0.8413 d. e. 0.3085

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