A van der Waals gas is going through a Joule–Thomson process that keeps the enthalpy H constant. A van der Waals gas in characterised by the following equations of state,

and the amount of gas is constant, i.e. N = const. Use the condition dH = 0 in order to obtain an expression for the derivative dT/dV. Determine the temperature T₀ at which this derivative changes sign.

Transcribed Image Text:

P = NRT V- Nb N² a 12 and U = CNRT - N² a V