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statistics
elementary statistics a step by step approach

Questions and Answers of Elementary Statistics A Step By Step Approach

Determine whether each statement is true or false. If the statement is false, explain why.For a specific confidence interval, the larger the sample size, the smaller the margin of error will be.
Find p̂ and q̂ for each percentage.a. n = 60 and X = 35b. n = 95 and X = 43c. 68%d. 55%e. 12%
Repeat Exercise 1, using a different variable and a sample of 15.Data from in Exercise 1From the Data Bank choose a variable, find the mean, and construct the 95 and 99% confidence intervals of the
Use 30 stocks classified as the Dow Jones industrials as the sample. Note the amount each stock has gained or lost in the last quarter. Compute the mean and standard deviation for the data set.
A confidence interval for a median can be found by using these formulasto define positions in the set of ordered data values. Suppose a data set has 30 values, and you want to find the 95% confidence
Determine whether each statement is true or false. If the statement is false, explain why.Interval estimates are preferred over point estimates since a confidence level can be specified.
In each case, find p̂ and q̂ .a. n = 80 and X = 40b. n = 200 and X = 90c. n = 130 and X = 60d. 25%e. 42%
From the Data Bank choose a variable, find the mean, and construct the 95 and 99% confidence intervals of the population mean. Use a sample of at least 30 subjects. Find the mean of the population,
Find P(z > 2.3 and z < - 1.2).
Find P(z < 2.3 or z > - 1.2).
For Exercises z0 is the statistical notation for an unknown z value. It serves that same function as x does in an algebraic equation.Find z0 such that P( - z0 < z < z0) = 0.76.
For Exercises z0 is the statistical notation for an unknown z value. It serves that same function as x does in an algebraic equation.Find z0 such that the area between z0 and z =-0.5 is 0.2345
For Exercises z0 is the statistical notation for an unknown z value. It serves that same function as x does in an algebraic equation.Find z0 such that P(z0 < z < 2.5) = 0.7672.
For Exercises z0 is the statistical notation for an unknown z value. It serves that same function as x does in an algebraic equation.Find z0 such that P( - 1.2 <z <z0) = 0.8671.
For Exercises find the z value that corresponds to the given area. 0.0188- N 0
The average GMAT scores for the top-30 ranked graduate schools of business are listed here. Check for normality. 718 703 703 703 700 690 695 705 690 688 676 681 689 686 691 669 674 652 680 670 651
In Exercises find the probabilities for each, using the standard normal distribution.P(1.12 < z < 1.43)
The number of calories contained in a selection of fast-food sandwiches is shown here. Check for normality.
In Exercises find the probabilities for each, using the standard normal distribution.P(1.51 < z < 2.17)
In Exercises find the probabilities for each, using the standard normal distribution.P(z <- 1.77)
The mean temperature (of daily maximum temperatures) in July for Dallas–Ft. Worth, Texas, is 85 degrees. Assuming a normal distribution, what would the standard deviation have to be if 10% of days
In Exercises find the probabilities for each, using the standard normal distribution.P(z <- 1.46)
In Exercises find the probabilities for each, using the standard normal distribution.P(z > 0.82)
Fifty-three percent of U.S. households have a personal computer. In a random sample of 250 households, what is the probability that fewer than 120 have a PC?
In Exercises find the probabilities for each, using the standard normal distribution.P(z > 2.51)
The percentage of U.S. households that have online connections is 44.9%. In a random sample of 420 households, what is the probability that fewer than 200 have online connections?
If 8% of all people in a certain geographic region are unemployed, find the probability that in a sample of 200 people, fewer than 10 people are unemployed.
In Exercises find the probabilities for each, using the standard normal distribution.P( - 1.43 < z < 0)
The average electric bill in a residential area is $72 for the month of April. The standard deviation is $6. If the amounts of the electric bills are normally distributed, find the probability that
In Exercises find the probabilities for each, using the standard normal distribution.P(0 < z < 0.92)
For Exercises find the area under the standard normal distribution curve.To the left of z = - 2.15 and to the right of z = 1.62
Membership in an elite organization requires a test score in the upper 30% range. If μ = 115 and σ = 12, find the lowest acceptable score that would enable a candidate to apply for membership.
The average thickness of books on a library shelf is 8.3 centimeters. The standard deviation is 0.6 centimeter. If 20% of the books are oversized, find the minimum thickness of the oversized books on
On the daily run of an express bus, the average number of passengers is 48. The standard deviation is 3. Assume the variable is normally distributed. Find the probability that the bus will havea.
The normal distribution can be used to approximate the binomial distribution when n · p and n · q are both greater than or equal to ________ .
For Exercises find the area under the standard normal distribution curve.To the right of z = - 0.12
For Exercises find the area under the standard normal distribution curve.To the left of z = 1.31
The average number of gallons of lemonade consumed by the football team during a game is 20, with a standard deviation of 3 gallons. Assume the variable is normally distributed. When a game is
For Exercises find the area under the standard normal distribution curve.To the left of z = 2.22
The average height of a certain age group of people is 53 inches. The standard deviation is 4 inches. If the variable is normally distributed, find the probability that a selected individual’s
For Exercises find the area under the standard normal distribution curve.Between z = - 1.46 and z = - 1.98
The average amount of rain per year in Greenville is 49 inches. The standard deviation is 8 inches. Find the probability that next year Greenville will receive the following amount of rainfall.
For Exercises find the area under the standard normal distribution curve.Between z = - 0.24 and z = - 1.12
Using the standard normal distribution, find each probability.a. P(0 < z < 2.16)b. P( - 1.87 < z < 0)c. P( - 1.63 < z < 2.17)d. P(1.72 < z < 1.98)e. P( -
For Exercises find the area under the standard normal distribution curve.Between z = 0.96 and z = 0.36
Find the area under the standard normal distribution for each.a. Between 0 and 1.50b. Between 0 and - 1.25c. Between 1.56 and 1.96d. Between - 1.20 and - 2.25e. Between - 0.06 and 0.73f. Between 1.10
For Exercises find the area under the standard normal distribution curve.Between z = 1.56 and z = 1.83
The average annual professor’s salary at a doctoral level at a private, independent institution is $159,964 for men and $147,702 for women. Consider the women’s salaries. Assume that they are
The correction factor for the central limit theorem should be used when the sample size is greater than ________ of the size of the population.
For Exercises find the area under the standard normal distribution curve.Between z = 1.23 and z = 1.90
For Exercises find the area under the standard normal distribution curve.Between z = 1.09 and z = 1.83
The standard deviation of all possible sample means is called the ________.
According to recent surveys, 60% of households have personal computers. If a random sample of 180 households is selected, what is the probability that more than 60 but fewer than 100 have a personal
When a distribution is positively skewed, the relationship of the mean, median, and mode from left to right will bea. Mean, median, modeb. Mode, median, mean c. Median, mode, meand. Mean, mode,
For Exercises find the area under the standard normal distribution curve.To the left of z = 0.75
The mean of the sample means equals ________.
In a recent year, 56% of employers offered a consumer-directed health plan (CDHP). This type of plan typically combines a high deductible with a health savings plan. Choose 80 employers at random.
In a recent year the average movie ticket cost $7.89. In a random sample of 50 movie tickets from various areas, what is the probability that the mean cost exceeds $8.00, given that the population
For Exercises find the area under the standard normal distribution curve.To the left of z = 1.39
Each American uses an average of 650 pounds (295 kg) of paper in a year. Suppose that the distribution is approximately normal with a population standard deviation of 153.5 pounds. Assume the
The difference between a sample mean and a population mean is due to ________.
For Exercises find the area under the standard normal distribution curve.To the right of z = 2.01
When one is using the standard normal distribution, P(z < 0) = ________.
For Exercises find the area under the standard normal distribution curve.To the right of z = 0.29
The standard deviation of all possible sample means equalsa. The population standard deviationb. The population standard deviation divided by the population meanc. The population standard deviation
The mean home price in Raleigh, North Carolina, is $217,600. Assuming that the home prices are normally distributed with a standard deviation of $36,400, what is the probability that a randomly
For Exercises find the area under the standard normal distribution curve.Between z = 0 and z = 0.32
In a recent year, 23.3% of Americans smoked cigarettes. What is the probability that in a random sample of 200 Americans, more than 50 smoke?
Use the normal approximation to find the probabilities for the specific value(s) of X.a. n = 10, p = 0.5, X ≥ 7b. n = 20, p = 0.7, X ≤ 12c. n = 50, p = 0.6, X ≤ 40
For Exercises find the area under the standard normal distribution curve.Between z = 0 and z = 2.14
Which is not a property of the standard normal distribution?a. It’s symmetric about the mean.b. It’s uniform.c. It’s bell-shaped.d. It’s unimodal.
Explain why the method used in step 7 works.
For Exercises find the area under the standard normal distribution curve.Between z = 0 and z = 1.77
Approximately what percentage of normally distributed data values will fall within 1 standard deviation above or below the mean?a. 68%b. 95% c. 99.7%d. Variable
To find an approximation of the standard deviation, locate the values on the x axis that correspond to the 16 and 84% values on the y axis. Subtract these two values and divide the result by 2.
The average weekly unemployment benefit in Montana is $272. Suppose that the benefits are normally distributed with a standard deviation of $43. A random sample of 15 benefits is chosen in Montana.
For Exercises find the area under the standard normal distribution curve.Between z = 0 and z = 0.98
The mean of the standard normal distribution isa. 0b. 1 c. 100d. Variable
Confirm the two formulas hold true for the central limit theorem for the population containing the elements {1, 5, 10}. First, compute the population mean and standard deviation for the data set.
To find an approximation of the mean or median, draw a horizontal line from the 50% point on the y axis over to the curve and then a vertical line down to the x axis. Compare this approximation of
Collect data regarding Math SAT scores to complete this problem. What are the mean and standard deviation for statewide Math SAT scores? What SAT score separates the bottom 10% of states from the
Determine whether each statement is true or false. If the statement is false, explain why.The central limit theorem applies to means of samples selected from different populations.
If the points fall approximately in a straight line, it can be concluded that the distribution is normal. Do you feel that this distribution is approximately normal? Explain your answer.
Determine whether each statement is true or false. If the statement is false, explain why.The area under the standard normal distribution to the left of z = 0 is negative.
When is the normal distribution not a good approximation for the binomial distribution?
Use the data regarding heart rates collected in data project 6 of Chapter 2 for this problem. Use the sample mean and standard deviation as estimates of the population parameters. For the
Using the normal probability paper shown in Table 6–3, label the x axis with the class boundaries as shown and plot the percents.Data from in Table 6-3 TABLE 6-3 98 99 96 90 80 70 30 40 50
Determine whether each statement is true or false. If the statement is false, explain why.The z value corresponding to a number below the mean is always negative.
Using the standard normal distribution, find each probability.a. P(0 < z < 2.07)b. P( - 1.83 < z < 0)c. P( - 1.59 < z < 2.01)d. P(1.33 < z
Use the data collected in data project 3 of Chapter 2 regarding song lengths. If the sample estimates for mean and standard deviation are used as replacements for the population parameters for this
Find the cumulative percents for each class by dividing each cumulative frequency by 200 (the total frequencies) and multiplying by 100%. (For the first class, it would be 24/200 ×100% = 12%.) Place
What is the mean of the sample means?
Determine whether each statement is true or false. If the statement is false, explain why.All variables that are approximately normally distributed can be transformed to standard normal variables.
Find the mean and standard deviation for the batting average for a player in the most recently completed MLB season. What batting average would separate the top 5% of all hitters from the rest? What
Find the cumulative frequencies for each class, and place the results in the third column.
Determine whether each statement is true or false. If the statement is false, explain why.The standard normal distribution is a continuous distribution.
Use the data collected in data project 1 of Chapter 2 regarding earnings per share to complete this problem. Use the mean and standard deviation computed in data project 1 of Chapter 3 as estimates
Sometimes a researcher must decide whether a variable is normally distributed. There are several ways to do this. One simple but very subjective method uses special graph paper, which is called
Determine whether each statement is true or false. If the statement is false, explain why.The total area under a normal distribution is infinite.
A study found that 1% of Social Security recipients are too young to vote. If 800 Social Security recipients are randomly selected, find the mean, variance, and standard deviation of the number of

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